[SOLVED] Telling the difference between mouse button drag and click

[jwvanderbeck]

Hello.

I have two states that are based on a mouse click.

Left mouse button and drag pans the camera.  I have this working fine.
Left mouse button click selects an object or point.  I have this working fine.

What I can't figure out how to do is how to get both working together.  I can't figure out how to transition to the proper state without one or the other taking precedence.

Is there a way to define a transition that essentially says "If the mouse button is down and the mouseX/Y is changing, then do this transition"?

[jwvanderbeck]

I managed to get this working.  The trick was understanding that the Mouse Pick action doesn't fire on a left click, which I erroneously thought.  It just fires a ray from the mouse position at any time requested, regardless of the state of the mouse.

So what I did was on Left Button Down I transition to a new state, "Left Button Down".  In that state I have three actions.  In one action I get the mouse movement (Get Axis Vector with axis of Mouse X and Mouse Y) and store the magnitude in a float.  In another action I use Float Changed to send a transition "Mouse Movement" if that float changes.  The last action is Get Mouse Button Up and fires a transition "Left Mouse Up".

"Mouse Movement" transitions to another state "Pan With Mouse" where I handle my panning.  "Left Mouse Up" transitions to a state "Mouse Up After Click" where I perform the Mouse Pick and carry on as normal from there.

So in a nutshell after I see the user has pressed the left mouse button down, I then look to see if he moved the mouse before he released the button.  If he releases the button without moving the mouse, then I transition to a pick, and if he moved the mouse first, I transition to a pan.

[Tack]

I'd like to thank you for coming back and posing the answer with a screenshot. This is extremely helpful!

[jwvanderbeck]

I'd like to thank you for coming back and posing the answer with a screenshot. This is extremely helpful!

You're welcome.  Nothing makes me crazier than finding someone else who solved the same problem I had in a search, only to see they didn't say how they solved it.  So I always try to follow up for future posterity.  For all I know, I might be solving my own problem again sometime in the future

[slcrubes]

Agreed...this is exactly what I was looking for. Thanks for posting that solution.